Write the measures of the sides of $\Delta PQR$ in ascending order,given that $\angle P = 93^{\circ}$ and $\angle R = 55^{\circ}$.

(A) In $\Delta PQR$,the sum of all angles is $180^{\circ}$.
$\angle P + \angle Q + \angle R = 180^{\circ}$
$93^{\circ} + \angle Q + 55^{\circ} = 180^{\circ}$
$148^{\circ} + \angle Q = 180^{\circ}$
$\angle Q = 180^{\circ} - 148^{\circ} = 32^{\circ}$.
Since the side opposite to the smallest angle is the shortest and the side opposite to the largest angle is the longest,we compare the angles: $\angle Q (32^{\circ}) < \angle R (55^{\circ}) < \angle P (93^{\circ})$.
Therefore,the sides in ascending order are: $PR < PQ < QR$.