Write the molecular formulae of all the compounds that can be formed by the combination of the following ions: $Cu^{2+}, Na^{+}, Fe^{3+}, Cl^{-}, SO_{4}^{2-}, PO_{4}^{3-}$.
(N/A) To form neutral compounds,the total positive charge must equal the total negative charge.
$1$. For $Cu^{2+}$:
- With $Cl^{-}$: $CuCl_{2}$
- With $SO_{4}^{2-}$: $CuSO_{4}$
- With $PO_{4}^{3-}$: $Cu_{3}(PO_{4})_{2}$
$2$. For $Na^{+}$:
- With $Cl^{-}$: $NaCl$
- With $SO_{4}^{2-}$: $Na_{2}SO_{4}$
- With $PO_{4}^{3-}$: $Na_{3}PO_{4}$
$3$. For $Fe^{3+}$:
- With $Cl^{-}$: $FeCl_{3}$
- With $SO_{4}^{2-}$: $Fe_{2}(SO_{4})_{3}$
- With $PO_{4}^{3-}$: $FePO_{4}$
$1$. For $Cu^{2+}$:
- With $Cl^{-}$: $CuCl_{2}$
- With $SO_{4}^{2-}$: $CuSO_{4}$
- With $PO_{4}^{3-}$: $Cu_{3}(PO_{4})_{2}$
$2$. For $Na^{+}$:
- With $Cl^{-}$: $NaCl$
- With $SO_{4}^{2-}$: $Na_{2}SO_{4}$
- With $PO_{4}^{3-}$: $Na_{3}PO_{4}$
$3$. For $Fe^{3+}$:
- With $Cl^{-}$: $FeCl_{3}$
- With $SO_{4}^{2-}$: $Fe_{2}(SO_{4})_{3}$
- With $PO_{4}^{3-}$: $FePO_{4}$
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