Write the products of the addition reaction $ >C = C < + XY \to $
- A$ > \mathop {\mathop C\limits_| }\limits_X - \mathop {\mathop C\limits_| }\limits_Y < $
- B$X - \mathop C\limits_| = \mathop C\limits_| - Y$
- C$\mathop C\limits_|^| = \mathop {\mathop C\limits_| }\limits_Y - $
- D$X - C - C - X$
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When vinyl and allyl radicals are joined together,we get:
Medium
View SolutionWhat is the product obtained when an alkene is reacted with cold and dilute alkaline potassium permanganate $(KMnO_4)$?
Consider the following reaction sequence:
$2-\text{Methylpropane}$ $\xrightarrow{KMnO_4} X$ $\xrightarrow[358 \ K]{20 \% \ H_3PO_4} Y$ $\xrightarrow[\text{(ii) } Zn \mid H_2O]{\text{(i) } O_3} A + B$
What are $A$ and $B$?
$2-\text{Methylpropane}$ $\xrightarrow{KMnO_4} X$ $\xrightarrow[358 \ K]{20 \% \ H_3PO_4} Y$ $\xrightarrow[\text{(ii) } Zn \mid H_2O]{\text{(i) } O_3} A + B$
What are $A$ and $B$?
DifficultTS EAMCET 2024
View SolutionWhat is the product obtained when phenylethene is treated with $KMnO_4$ in dilute $H_2SO_4$?
Assertion $(A)$: Reaction of $but-1-ene$ with $HBr$ gives $1-bromobutane$ as the major product.
Reason $(R)$: Addition of $HBr$ to unsymmetrical alkenes proceeds according to Markovnikov's rule.
The correct answer is
Reason $(R)$: Addition of $HBr$ to unsymmetrical alkenes proceeds according to Markovnikov's rule.
The correct answer is
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