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(C) $NaBH_4$ (Sodium borohydride) is a selective reducing agent that reduces aldehydes and ketones to their corresponding alcohols,but it does not red

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(C) $NaBH_4$ (Sodium borohydride) is a selective reducing agent that reduces aldehydes and ketones to their corresponding alcohols,but it does not reduce esters under normal conditions.In the given molecule,there is a ketone group in the cyclohexane ring and an ester group $(-COOCH_3)$.$NaBH_4$ will selectively reduce the ketone group to a secondary alcohol $(-CH(OH)-)$ while leaving the ester group intact.Therefore,the product is a molecule with a cyclohexanol ring attached to a $-CH_2-COOCH_3$ group.This corresponds to the structure shown in option $C$.

Write the structure of the product of the following reaction.

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