Write the structures of fragments produced on complete hydrolysis of $DNA$? How are they linked in $DNA$ molecule? Draw the diagram to show pairing of nucleotide bases in double helix of $DNA$?
(N/A) Complete hydrolysis of $DNA$ yields three types of fragments:
$1$. $A$ pentose sugar $(2-deoxy-D-ribose)$.
$2$. Phosphoric acid $(H_3PO_4)$.
$3$. Nitrogenous bases: Adenine $(A)$,Guanine $(G)$,Cytosine $(C)$,and Thymine $(T)$.
In a $DNA$ molecule,these fragments are linked as follows:
- The nitrogenous base is attached to the $C1'$ position of the $2-deoxy-D-ribose$ sugar via a $\beta-N-glycosidic$ linkage to form a nucleoside.
- The phosphoric acid is attached to the $C5'$ position of the sugar via a phosphodiester linkage to form a nucleotide.
- Nucleotides are linked together by $3'-5'$ phosphodiester bonds to form the polynucleotide chain.
Base pairing in the $DNA$ double helix occurs via hydrogen bonds:
- Adenine $(A)$ pairs with Thymine $(T)$ via two hydrogen bonds $(A=T)$.
- Guanine $(G)$ pairs with Cytosine $(C)$ via three hydrogen bonds $(G\equiv C)$.
$1$. $A$ pentose sugar $(2-deoxy-D-ribose)$.
$2$. Phosphoric acid $(H_3PO_4)$.
$3$. Nitrogenous bases: Adenine $(A)$,Guanine $(G)$,Cytosine $(C)$,and Thymine $(T)$.
In a $DNA$ molecule,these fragments are linked as follows:
- The nitrogenous base is attached to the $C1'$ position of the $2-deoxy-D-ribose$ sugar via a $\beta-N-glycosidic$ linkage to form a nucleoside.
- The phosphoric acid is attached to the $C5'$ position of the sugar via a phosphodiester linkage to form a nucleotide.
- Nucleotides are linked together by $3'-5'$ phosphodiester bonds to form the polynucleotide chain.
Base pairing in the $DNA$ double helix occurs via hydrogen bonds:
- Adenine $(A)$ pairs with Thymine $(T)$ via two hydrogen bonds $(A=T)$.
- Guanine $(G)$ pairs with Cytosine $(C)$ via three hydrogen bonds $(G\equiv C)$.
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Similar Questions
Given below are two statements:
Assertion $(A)$: Hydrolysis of $DNA$ does not form equal number of $A$ and $T$; $G$ and $C$.
Reason $(R)$: In $DNA$,adenine forms hydrogen bonds with thymine and cytosine forms hydrogen bonds with guanine.
The correct answer is:
Assertion $(A)$: Hydrolysis of $DNA$ does not form equal number of $A$ and $T$; $G$ and $C$.
Reason $(R)$: In $DNA$,adenine forms hydrogen bonds with thymine and cytosine forms hydrogen bonds with guanine.
The correct answer is:
Identify the nitrogen atom of a purine base that bonds with the $1^{\prime}$ carbon of ribose to form a ribonucleoside.
The double helical structure of $DNA$ was proposed by
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