Write 'True' or 'False' and justify your answ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The statement is False.We know that in the interval $0^{\circ} < 	heta < 90^{\circ}$,the function $\sin 	heta$ is an increasing function,while $

Vedclass · Accepted Answer

False

Vedclass · Answer

(B) The statement is False.We know that in the interval $0^{\circ} At $	heta = 45^{\circ}$,$\sin 45^{\circ} = \cos 45^{\circ} = \frac{1}{\sqrt{2}}$.For any angle $	heta$ such that $45^{\circ}  \cos 	heta$.Since $80^{\circ}$ lies in the interval $(45^{\circ}, 90^{\circ})$,we have $\sin 80^{\circ} > \cos 80^{\circ}$.Therefore,$(\sin 80^{\circ} - \cos 80^{\circ}) > 0$,which means the value is positive,not negative.

Write 'True' or 'False' and justify your answer.
The value of the expression $(\sin 80^{\circ} - \cos 80^{\circ})$ is negative.

Similar Questions

$5 \cos A = 4 \sin A$,then $\tan A = \ldots$

Given $\tan A = \frac{4}{3},$ find the other trigonometric ratios of the $\angle A$.

If $4 \tan \theta = 3,$ then $\left(\frac{4 \sin \theta - \cos \theta}{4 \sin \theta + \cos \theta}\right)$ is equal to

If $\sec \theta = \frac{13}{5}$,then $\cos \theta = \ldots \ldots \ldots \ldots$

Write 'True' or 'False' and justify your answer.
$\cos \theta = \frac{a^{2} + b^{2}}{2ab}$,where $a$ and $b$ are two distinct numbers such that $ab > 0$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Write 'True' or 'False' and justify your answer.The value of the expression $(\sin 80^{\circ} - \cos 80^{\circ})$ is negative.