State whether the following statement is true or false:
$-273^{\circ} C = 0 K$
$-273^{\circ} C = 0 K$
(TRUE) The statement is True.
The relationship between the Celsius scale and the Kelvin scale is given by the formula: $T(K) = T(^{\circ}C) + 273.15$.
For standard calculations,we use the approximation $T(K) = T(^{\circ}C) + 273$.
Substituting $T(^{\circ}C) = -273$,we get $T(K) = -273 + 273 = 0 K$.
Therefore,$-273^{\circ} C$ is equivalent to absolute zero,which is $0 K$.
The relationship between the Celsius scale and the Kelvin scale is given by the formula: $T(K) = T(^{\circ}C) + 273.15$.
For standard calculations,we use the approximation $T(K) = T(^{\circ}C) + 273$.
Substituting $T(^{\circ}C) = -273$,we get $T(K) = -273 + 273 = 0 K$.
Therefore,$-273^{\circ} C$ is equivalent to absolute zero,which is $0 K$.
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