Young's double slit experiment is performed with light of wavelength $550 \, nm$. The separation between the slits is $1.10 \, mm$ and the screen is placed at a distance of $1 \, m$. What is the distance between consecutive bright or dark fringes in $mm$?

An interference pattern was made by using red light. If the red light is replaced with blue light,the fringes will become

In a Young's double-slit experiment,the fringe width is $0.2 \, mm$. If the wavelength of light is increased by $10\%$ and the distance between the slits is increased by $10\%$,then the new fringe width will be ..... $mm$.

In Young's double-slit experiment,when two light waves form the third minimum,the path difference between them is:

In the double slit experiment,when a glass plate (refractive index $\mu = 1.5$) of thickness $t$ is introduced in the path of one of the interfering beams (wavelength $\lambda$),the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass plate is

In a Young's double slit experiment,two slits are illuminated with light of wavelength $\lambda = 800 \, nm$. The line joining $A_1 P$ is perpendicular to $A_1 A_2$ as shown in the figure. If the first minimum is detected at $P$,the value of slit separation '$a$' will be $......... \, mm$. The distance of the screen from the slits is $D = 5 \, cm$.