Zinc (II) ion on reaction with NaOH first giv | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Zinc $(II)$ ions react with sodium hydroxide to form a white precipitate of zinc hydroxide:$Zn^{2+}(aq) + 2OH^-(aq) \rightarrow Zn(OH)_2(s)$ (whit

Vedclass · Accepted Answer

$[Zn(OH)_4]^{2-}$

Vedclass · Answer

(C) Zinc $(II)$ ions react with sodium hydroxide to form a white precipitate of zinc hydroxide:$Zn^{2+}(aq) + 2OH^-(aq) \rightarrow Zn(OH)_2(s)$ (white precipitate)When excess $NaOH$ is added,the white precipitate of zinc hydroxide dissolves due to the formation of the soluble tetrahydroxozincate $(II)$ complex:$Zn(OH)_2(s) + 2OH^-(aq) \rightarrow [Zn(OH)_4]^{2-}(aq)$

Zinc $(II)$ ion on reaction with $NaOH$ first gives a white precipitate which dissolves in excess of $NaOH$ due to the formation of:

Similar Questions

Which of the following statements is correct for a highly pure dilute solution of sodium in liquid ammonia?

$KO_2 + CO_2 + H_2O \xrightarrow{\text{more } CO_2} [X] + [Y]$
Products $[X]$ and $[Y]$ are respectively

Excess of $Na^{+}$ ions in our system causes:

Among alkali metals,which element do you expect to be least electronegative and why?

Sodium hydroxide is produced on a large scale:

Vedclass Test Series

Exam Paper Generator

Online Exam Module