Zinc reacts with hydrochloric acid to give hy | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The balanced chemical equation is: $Zn(s) + 2HCl(aq) ightarrow ZnCl_2(aq) + H_2(g) \uparrow$Moles of $Zn$ used $= \frac{	ext{mass}}{	ext{molar

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) The balanced chemical equation is: $Zn(s) + 2HCl(aq) ightarrow ZnCl_2(aq) + H_2(g) \uparrow$Moles of $Zn$ used $= \frac{	ext{mass}}{	ext{molar mass}} = \frac{11.5 \ g}{65.4 \ g \ mol^{-1}} \approx 0.1758 \ mol$.According to the stoichiometry of the reaction,$1 \ mol$ of $Zn$ produces $1 \ mol$ of $H_2$.Therefore,moles of $H_2$ produced $= 0.1758 \ mol$.Volume of $H_2$ at $STP = 	ext{moles} 	imes 	ext{molar volume at } STP = 0.1758 \ mol 	imes 22.7 \ L \ mol^{-1} \approx 3.99 \ L$.Rounding to the nearest integer,the volume is $4 \ L$.

Similar Questions

If $100 \ mL$ of $1 \ N$ sulphuric acid were mixed with $100 \ mL$ of $1 \ M$ sodium hydroxide,the solution will be

When the same amount of zinc is treated separately with an excess of sulphuric acid and an excess of sodium hydroxide solution,the ratio of the volumes of hydrogen evolved is:

What is the normality of a $1 \, M$ solution of $H_3PO_4$?

If a $100 \ mL$ solution contains $X \ g$ of $Na_2CO_3$ and its concentration is $Y \ M$,then $X$ and $Y$ are respectively ...............

The amount of carbon dioxide evolved upon complete combustion of $116 \ g$ of $n$-butane is
(Given : atomic mass in amu $H = 1, C = 12$ and $O = 16$) (in $g$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module