Predict the product of the following reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given reaction is an intramolecular Cannizzaro reaction. Aldehydes that do not have $\alpha$-hydrogen atoms undergo self-oxidation and reducti

Vedclass · Accepted Answer

Vedclass · Answer

(C) The given reaction is an intramolecular Cannizzaro reaction. Aldehydes that do not have $\alpha$-hydrogen atoms undergo self-oxidation and reduction (disproportionation) in the presence of concentrated alkali. In the given molecule,$2,2',6,6'$-tetraformylbiphenyl,the aldehyde groups are present on the benzene rings. Upon treatment with excess $NaOH$,two of the $-CHO$ groups are reduced to $-CH_2OH$ (alcohol) groups,and the other two $-CHO$ groups are oxidized to $-COO^-$ (carboxylate) groups. Subsequent acidification with $H^+/H_2O$ converts the carboxylate groups into $-COOH$ (carboxylic acid) groups. Thus,the final product contains two $-CH_2OH$ groups and two $-COOH$ groups.

Predict the product of the following reaction:
$2,2',6,6'$-tetraformylbiphenyl $\xrightarrow[(ii)\,H^{+}/H_2O, 0^{\circ}C]{(i)\,NaOH (excess)}$ ?

Similar Questions

Aldol condensation will not be observed in

Arrange the following compounds in increasing order of their enol content:
$1. CH_3CHO$
$2. CH_3COCH_3$
$3. CH_3COCH_2CHO$
$4. CH_3COCH_2COCH_3$

Which among the following is the correct structure of the semicarbazone formed when ethanal reacts with semicarbazide?

Which is the best oxidizing agent to oxidize $CH_3CH=CHCHO$ to $CH_3CH=CHCOOH$?

Which statement about the aldol condensation is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Predict the product of the following reaction:$2,2',6,6'$-tetraformylbiphenyl $\xrightarrow[(ii)\,H^{+}/H_2O, 0^{\circ}C]{(i)\,NaOH (excess)}$ ?