The reaction of CH_3-CH=C(CH_3)-CH=CH_2 with | vedclass

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(A) The reaction is reductive ozonolysis of the given alkene,$CH_3-CH=C(CH_3)-CH=CH_2$.In reductive ozonolysis,the $C=C$ double bonds are cleaved,and

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$CH_3-CH=O, CH_3-CO-CHO, H_2C=O$

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(A) The reaction is reductive ozonolysis of the given alkene,$CH_3-CH=C(CH_3)-CH=CH_2$.In reductive ozonolysis,the $C=C$ double bonds are cleaved,and each carbon atom of the double bond is converted into a carbonyl group $(C=O)$.$1$. The first double bond $CH_3-CH=C...$ cleaves to form $CH_3-CHO$ (acetaldehyde) and the fragment $O=C(CH_3)-CH=CH_2$.$2$. The second double bond $...-C(CH_3)-CH=CH_2$ cleaves to form the fragment $CH_3-CO-CHO$ (methylglyoxal) and $H_2C=O$ (formaldehyde).Thus,the products are $CH_3-CHO, CH_3-CO-CHO$,and $H_2C=O$.

The reaction of $CH_3-CH=C(CH_3)-CH=CH_2$ with $(1) \ O_3$ followed by $(2) \ H_2O, Zn$ gives which products?

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