The reaction sequence is as follows: CH(COOK) | vedclass

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(A) $1$. The electrolysis of an aqueous solution of potassium maleate (or fumarate) is a Kolbe electrolysis reaction.$2$. The reaction is: $CH(COOK)=C

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$CH_3-CH=O$

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(A) $1$. The electrolysis of an aqueous solution of potassium maleate (or fumarate) is a Kolbe electrolysis reaction.$2$. The reaction is: $CH(COOK)=CH(COOK) + 2H_2O \xrightarrow{	ext{electrolysis}} CH \equiv CH + 2CO_2 + H_2 + 2KOH$.$3$. Thus,$X$ is acetylene $(CH \equiv CH)$.$4$. The hydration of acetylene in the presence of $Hg^{2+}$ and $dil. H_2SO_4$ (Kucherov reaction) yields acetaldehyde $(CH_3CHO)$.$5$. The reaction is: $CH \equiv CH + H_2O$ $\xrightarrow{Hg^{2+}/H_2SO_4} [CH_2=CH-OH]$ $ightarrow CH_3-CH=O$.$6$. Therefore,$Y$ is $CH_3-CH=O$.

The reaction sequence is as follows:
$CH(COOK)=CH(COOK)_{(aq)}$ $\xrightarrow{\text{electrolysis}} X$ $\xrightarrow[Hg^{2+}]{dil. H_2SO_4} Y$; $Y$ is

Similar Questions

What will be $X$ in the following reaction?
${C_2}{H_2} \xrightarrow[{HgSO_4 / H_2SO_4, 60^{\circ}C}]{{H_2O}} X \rightleftharpoons CH_3CHO$

The product $(B)$ of the reaction is:
$CH(CO_2H)=CH(CO_2H)$ $\xrightarrow[2 \ mole]{NaOH} (A)$ $\xrightarrow{\text{electrolysis}} (B)$

Reactant $P$ (an alkyne) gives products $Q$ (trans-alkene) or $R$ (cis-alkene).
The possible reagents are:
$(I) \ 2Na/liq. NH_3$
$(II) \ H_2/Pd/CaCO_3$ (quinoline)
$(III) \ 2H_2/Pd/C$
Which of the following statements is/are correct with respect to the above conversion?

$CH_3-C \equiv C-O-CH_3 \xrightarrow{dil. H_2SO_4, HgSO_4} \text{major product}$

In which reaction is the final product $Ph-C \equiv CH$?

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The reaction sequence is as follows: $CH(COOK)=CH(COOK)_{(aq)}$ $\xrightarrow{\text{electrolysis}} X$ $\xrightarrow[Hg^{2+}]{dil. H_2SO_4} Y$; $Y$ is