The $T_4$ bacteriophage $rII$ mutant strain fails to lyse $E. coli$. However,when two strains $rII^X$ and $rII^Y$ are mixed,they lyse $E. coli$. What is the possible reason for this?

  • A
    The bacteriophage undergoes transformation into an uncoordinated form.
  • B
    No mutation occurs in them.
  • C
    Both strains have the same cistron.
  • D
    Both strains have different cistrons.

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Similar Questions

Match the following columns:
Column-$I$Column-$II$Column-$III$
$(1) \ 1952$$(a)$ Watson and Crick$(i)$ Double helix model of $DNA$
$(2) \ 1928$$(b)$ Friedrich Miescher$(ii)$ Proof that $DNA$ is genetic material
$(3) \ 1869$$(c)$ Griffith$(iii)$ Nuclein
$(4) \ 1953$$(d)$ Hershey and Chase$(iv)$ Transforming principle

In which process does the transfer of genetic information occur from $RNA$ to $DNA$?

Which of the following contains the essential enzymes for protein synthesis?

How many of the following statements are correct?
$I - RNA$ is formed from $DNA$ by the process of transcription.
$II - DNA$ is more stable than $RNA$.
$III - RNA$ acts as a catalyst (enzyme) in some biochemical reactions.
$IV - DNA$ is resistant to mutations due to its double-helical structure and the presence of complementary strands that allow for repair mechanisms.

Distinguish between: $m-RNA$ and $t-RNA$.

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