1.0 g of an oxide of A contained 0.5 g of A | vedclass

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(D) In the first oxide: $0.5 \ g$ of $A$ combines with $(1.0 - 0.5) = 0.5 \ g$ of oxygen.So,$1 \ g$ of $A$ combines with $1 \ g$ of oxygen.In the seco

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Multiple proportions

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(D) In the first oxide: $0.5 \ g$ of $A$ combines with $(1.0 - 0.5) = 0.5 \ g$ of oxygen.So,$1 \ g$ of $A$ combines with $1 \ g$ of oxygen.In the second oxide: $1.6 \ g$ of $A$ combines with $(4.0 - 1.6) = 2.4 \ g$ of oxygen.So,$1 \ g$ of $A$ combines with $(2.4 / 1.6) = 1.5 \ g$ of oxygen.The ratio of the masses of oxygen that combine with a fixed mass $(1 \ g)$ of $A$ is $1 : 1.5$,which is $2 : 3$.Since this ratio is a simple whole number ratio,the data illustrate the law of multiple proportions.

$1.0 \ g$ of an oxide of $A$ contained $0.5 \ g$ of $A$. $4.0 \ g$ of another oxide of $A$ contained $1.6 \ g$ of $A$. The data indicate the law of:

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