$2-$pentanone can be distinguished from $3-$pentanone by the reagent:

  • A
    $2,4-$dinitrophenylhydrazine
  • B
    Tollens reagent
  • C
    $I_2$ and dil. $NaOH$
  • D
    $NaHSO_3$

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$Ph_2CH-C(=O)H \xrightarrow{\text{aqueous acid}} (A) (81\%) + \text{enol} (2\%) + \text{aldehyde} (17\%)$. Product $(A)$ of the above reaction will be:

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Reactant $(A)$ is:

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