$1 \, \text{mol}$ of $CH_4$ contains
- A$6.02 \times 10^{23}$ atoms of $H$
- B$4 \, \text{g}$ atom of Hydrogen
- C$1.81 \times 10^{23}$ molecules of $CH_4$
- D$3.0 \, \text{g}$ of carbon
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