What will be the product (A) in the following | vedclass

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(A) The reaction of $p$-cresol with $CHCl_3$ and $KOH$ is a Reimer-Tiemann reaction.In the Reimer-Tiemann reaction,a formyl group $(-CHO)$ is introduc

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$2-$hydroxy$-5-$methylbenzaldehyde

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(A) The reaction of $p$-cresol with $CHCl_3$ and $KOH$ is a Reimer-Tiemann reaction.In the Reimer-Tiemann reaction,a formyl group $(-CHO)$ is introduced into the ortho position of the phenol ring.For $p$-cresol,the para position is already occupied by a methyl group $(-CH_3)$.Therefore,the formyl group will be introduced at the ortho position relative to the hydroxyl $(-OH)$ group.This results in the formation of $2$-hydroxy-$5$-methylbenzaldehyde.

What will be the product $(A)$ in the following reaction?
$p$-cresol $\xrightarrow[(ii) H^+]{(i) CHCl_3/KOH} (A)$

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What will be the product $(A)$ in the following reaction?$p$-cresol $\xrightarrow[(ii) H^+]{(i) CHCl_3/KOH} (A)$