1 , mol of oxygen gas is heated at constant v | vedclass

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(A) For an ideal gas,the relationship between molar heat capacities is $C_P - C_V = R$. Given $C_P = 7.03 \, cal \, mol^{-1} \, K^{-1}$ and $R = 2 \,

Vedclass · Accepted Answer

$50.3$

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(A) For an ideal gas,the relationship between molar heat capacities is $C_P - C_V = R$. Given $C_P = 7.03 \, cal \, mol^{-1} \, K^{-1}$ and $R = 2 \, cal \, mol^{-1} \, K^{-1}$,we calculate $C_V = C_P - R = 7.03 - 2 = 5.03 \, cal \, mol^{-1} \, K^{-1}$. The change in internal energy $\Delta E$ for a process at constant volume is given by $\Delta E = n C_V \Delta T$. Here,$n = 1 \, mol$,$C_V = 5.03 \, cal \, mol^{-1} \, K^{-1}$,and $\Delta T = 30 - 20 = 10 \, K$. Therefore,$\Delta E = 1 	imes 5.03 	imes 10 = 50.3 \, cal$.

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