C_2H_5-Br + CH_3ONa to A xrightarrow[{(cold)} | vedclass

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(D) Step $1$: The reaction of $C_2H_5Br$ with $CH_3ONa$ is a Williamson ether synthesis,which produces ethyl methyl ether $(A = C_2H_5-O-CH_3)$.Step $

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$CH_3I + C_2H_5OH$

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(D) Step $1$: The reaction of $C_2H_5Br$ with $CH_3ONa$ is a Williamson ether synthesis,which produces ethyl methyl ether $(A = C_2H_5-O-CH_3)$.Step $2$: When $C_2H_5-O-CH_3$ reacts with cold $HI$,the cleavage of the $C-O$ bond occurs.Step $3$: Since the ethyl group is primary and the methyl group is primary,the reaction follows an $S_N2$ mechanism where the iodide ion attacks the less sterically hindered methyl group.Step $4$: The products formed are $C_2H_5OH$ and $CH_3I$.

$C_2H_5-Br + CH_3ONa \to A \xrightarrow[{(cold)}]{{HI}} B,$ product $B$ is

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