A xrightarrow[{CHCl_3}]{{KOH}} B xrightarrow[ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The final product is $CH_3CH_2NHCH_3$ ($N$-methylethanamine).Step $1$: The reaction $B \xrightarrow[{H^\oplus}]{{LiAlH_4}} CH_3CH_2NHCH_3$ involve

Vedclass · Accepted Answer

$CH_3CH_2NH_2$

Vedclass · Answer

(A) The final product is $CH_3CH_2NHCH_3$ ($N$-methylethanamine).Step $1$: The reaction $B \xrightarrow[{H^\oplus}]{{LiAlH_4}} CH_3CH_2NHCH_3$ involves the reduction of an amide or an imine. Since $LiAlH_4$ reduces amides to amines,$B$ must be $CH_3CH_2CONHCH_3$.Step $2$: The reaction $A \xrightarrow[{CHCl_3}]{{KOH}} B$ is a carbylamine-like reaction or an alkylation. However,looking at the structure of $B$ $(CH_3CH_2CONHCH_3)$,it is an $N$-substituted amide. This suggests $A$ is the primary amine $CH_3CH_2NH_2$ reacting with an acylating agent,but the reagents $CHCl_3/KOH$ are characteristic of the Carbylamine test for primary amines.Step $3$: Re-evaluating the sequence: $CH_3CH_2NH_2$ $(A)$ reacts with $CHCl_3/KOH$ to form an isocyanide $(CH_3CH_2NC)$,which is not $B$. Given the options and the transformation,the reaction sequence likely represents the formation of an amide from an amine and an acid derivative,or a specific pathway. Based on standard chemistry problems of this type,$A$ is $CH_3CH_2NH_2$.

$A$ $\xrightarrow[{CHCl_3}]{{KOH}} B$ $\xrightarrow[{H^\oplus}]{{LiAlH_4}} CH_3CH_2NHCH_3$
Identify compound $A$.

Similar Questions

Which of the following reactions are used in the preparation of aliphatic primary amines?
$I$. Gabriel-phthalimide reaction
$II$. Hoffmann Bromamide reaction
$III$. Carbylamine reaction
$IV$. Sandmeyer reaction

Which is a better reagent for the reduction of an aryl nitro compound to an amine?

The given reaction $CH_3-C(C_2H_5)(C_3H_7)-COOH \xrightarrow{N_3H/Conc. H_2SO_4} CH_3-C(C_2H_5)(C_3H_7)-NH_2$ is called:

An aromatic compound $A$ having molecular formula $C_7H_6O_2$ on treating with aqueous ammonia and heating forms compound $B$. The compound $B$ on reaction with molecular bromine and potassium hydroxide provides compound $C$ having molecular formula $C_6H_7N$. The structure of $A$ is

Amides may be converted into amines by a reaction named after:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ $\xrightarrow[{CHCl_3}]{{KOH}} B$ $\xrightarrow[{H^\oplus}]{{LiAlH_4}} CH_3CH_2NHCH_3$Identify compound $A$.