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(A) $1$. Compound $A$ is $C_7H_6O_2$. When treated with aqueous ammonia and heated,it forms compound $B$. This suggests $A$ is benzoic acid $(C_6H_5CO

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Benzoic acid

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(A) $1$. Compound $A$ is $C_7H_6O_2$. When treated with aqueous ammonia and heated,it forms compound $B$. This suggests $A$ is benzoic acid $(C_6H_5COOH)$,which reacts with $NH_3$ to form ammonium benzoate,and upon heating,it dehydrates to form benzamide $(C_6H_5CONH_2)$ as compound $B$.$2$. Compound $B$ (benzamide,$C_6H_5CONH_2$) reacts with $Br_2$ and $KOH$ (Hofmann bromamide degradation) to form aniline $(C_6H_5NH_2)$ as compound $C$.$3$. The molecular formula of aniline is $C_6H_7N$,which matches the given formula for $C$.$4$. Therefore,compound $A$ is benzoic acid.

An aromatic compound $A$ having molecular formula $C_7H_6O_2$ on treating with aqueous ammonia and heating forms compound $B$. The compound $B$ on reaction with molecular bromine and potassium hydroxide provides compound $C$ having molecular formula $C_6H_7N$. The structure of $A$ is

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