Which of the following does not give RNH_2 vi | vedclass

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Question

(B) The Hofmann hypobromide degradation reaction is specific to primary amides $(RCONH_2)$.$RCONH_2 + Br_2 + 4NaOH \rightarrow RNH_2 + Na_2CO_3 + 2NaB

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Carbamide

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(B) The Hofmann hypobromide degradation reaction is specific to primary amides $(RCONH_2)$.$RCONH_2 + Br_2 + 4NaOH \rightarrow RNH_2 + Na_2CO_3 + 2NaBr + 2H_2O$.Carbamide,also known as urea $(NH_2CONH_2)$,is a diamide. When subjected to the Hofmann hypobromide reaction,it does not yield a simple primary amine $(RNH_2)$ as the final product because the reaction conditions lead to further degradation or decomposition of the intermediate species.Isobutanamide ($CH_3)_2CHCONH_2$,Ethanamide $(CH_3CONH_2)$,and Benzamide $(C_6H_5CONH_2)$ are all primary amides and will successfully undergo the Hofmann hypobromide reaction to form their respective primary amines.

Which of the following does not give $RNH_2$ via the Hofmann hypobromide reaction?

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