An aromatic compound 'A' on treatment with aq | vedclass

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Question

(C) The reaction sequence is as follows:$1$. Compound $A$ ($C_6H_5COOH$,benzoic acid) reacts with aqueous ammonia $(NH_3)$ followed by heating to form

Vedclass · Accepted Answer

$C_6H_5COOH$,$C_6H_5CONH_2$,$C_6H_5NH_2$

Vedclass · Answer

(C) The reaction sequence is as follows:$1$. Compound $A$ ($C_6H_5COOH$,benzoic acid) reacts with aqueous ammonia $(NH_3)$ followed by heating to form compound $B$ ($C_6H_5CONH_2$,benzamide).$2$. Benzamide $(C_6H_5CONH_2)$ undergoes the Hofmann bromamide degradation reaction with $Br_2$ and $KOH$ to form compound $C$ ($C_6H_5NH_2$,aniline).$3$. The molecular formula of aniline is $C_6H_7N$,which matches the given formula.Therefore,the correct sequence is $A = C_6H_5COOH$,$B = C_6H_5CONH_2$,and $C = C_6H_5NH_2$.

An aromatic compound '$A$' on treatment with aqueous ammonia and heating forms compound '$B$',which on heating with $Br_2$ and $KOH$ forms a compound $C$ of molecular formula $C_6H_7N$. The structures of compound $A, B$ and $C$ are respectively:

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