$CH_3-CH=CH_2$ $\xrightarrow{Br_2, hv (\text{low conc.})} \dots$ $\xrightarrow{Mg, \text{Dry ether}} \dots$ $\xrightarrow{CH_3-CO-CH_3, NH_4Cl} \dots$ $\xrightarrow{H^{+}, \Delta} (X)$. The end product $(X)$ of the above reaction is:

  • A
    $CH_2=CH-CH_2-C(=CH_2)-CH_3$
  • B
    $CH_2=CH-CH=C(CH_3)_2$
  • C
    $CH_2=CH-CH_2-C(OH)(CH_3)_2$
  • D
    $CH_2=CH-CH_2-CH(CH_3)-CH_2-OH$

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Find the stability order of the following compounds:

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Write the main product of the given reactions:
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$

Write the main product of the given reactions:
$1$. $CH_3-CH=CH-CH_3 \xrightarrow[cold, Na_2CO_3]{KMnO_4}$
$2$. $2,3-$Dimethylbut$-2-$ene $\xrightarrow{Baeyer\ test}$

Addition of $HBr$ to propene yields $2-$bromopropane,while in the presence of benzoyl peroxide,the same reaction yields $1-$bromopropane. Explain and give the mechanism.

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