The reaction of N-ethylcyclohexanamine with e | vedclass

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(D) The reaction involves the nucleophilic substitution of $CH_3I$ by the nitrogen atom of the amine. Since $CH_3I$ is present in excess,the amine und

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a quaternary ammonium salt

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(D) The reaction involves the nucleophilic substitution of $CH_3I$ by the nitrogen atom of the amine. Since $CH_3I$ is present in excess,the amine undergoes exhaustive methylation. The secondary amine ($N$-ethylcyclohexanamine) reacts with $CH_3I$ to form a tertiary amine,which further reacts with another molecule of $CH_3I$ to form a quaternary ammonium salt. The final product is a quaternary ammonium salt,specifically $N,N$-dimethyl-$N$-ethylcyclohexanaminium iodide.

The reaction of $N$-ethylcyclohexanamine with excess $CH_3I$ yields a product. Identify the product.

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