CH_3-CH(CH_3)-CH_3 + CH_2=CH_2 xrightarrow[2. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of isobutane with ethene in the presence of $HF$ at low temperature is an alkylation reaction.$1$. The mechanism involves the formati

Vedclass · Accepted Answer

$CH_3-C(CH_3)_2-CH_2-CH_3$

Vedclass · Answer

(C) The reaction of isobutane with ethene in the presence of $HF$ at low temperature is an alkylation reaction.$1$. The mechanism involves the formation of a tert-butyl carbocation $(CH_3)_3C^+$ by the protonation of isobutane.$2$. This carbocation adds to the ethene molecule to form a new carbocation $(CH_3)_3C-CH_2-CH_2^+$.$3$. Through a series of rearrangements ($1$,$2$-hydride shift followed by $1,2-$methyl shift),a more stable carbocation is formed.$4$. Finally,hydride abstraction from another isobutane molecule yields the major product,$2$,$2$-dimethylbutane $(CH_3-C(CH_3)_2-CH_2-CH_3)$.

$CH_3-CH(CH_3)-CH_3 + CH_2=CH_2 \xrightarrow[2.5^oC]{HF} (A)$; $(A)$ is:

Similar Questions

One mole of an alkane $(x)$ requires $8$ mole oxygen for complete combustion. The sum of the number of carbon and hydrogen atoms in the alkane $(x)$ is . . . . . . .

Which of the following statements is incorrect regarding the members of the homologous series of alkanes?

Briefly explain the trends in boiling point and melting point in the alkane series.

$R^{\prime}-X \xrightarrow{Na / \text{ether}} 2,3-\text{dimethylbutane}$. Identify $R^{\prime}$.

$A$ gaseous alkane undergoes complete combustion with oxygen. The ratio of the volume of $O_2$ required to the volume of $CO_2$ formed is $7 : 4$. The molecular formula of the alkane is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module