$1, 2, 3$-butanetriol undergoes oxidative cleavage with $HIO_4$. During this process:

• A
  $1$ equivalent of $HIO_4$ is consumed and $HCO_2H$ and $CH_3-C(=O)-CO_2H$ are formed.
• B
  $2$ equivalents of $HIO_4$ are consumed and $HCO_2H, HCH=O$ and $CH_3-CH=O$ are formed.
• C
  $3$ equivalents of $HIO_4$ are consumed and $2$ eq. of $HCO_2H$ and $1$ eq. of $CH_3CO_2H$ are formed.
• D
  $2$ equivalents of $HIO_4$ are consumed and $2$ eq. of $HCO_2H$ and $1$ eq. of $CH_3CH=O$ are formed.