(i) CHO-(CHOH)_3-CH_2OH xrightarrow{4HIO_4} | vedclass

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(C) In reaction $(i)$,the oxidation of aldopentose with $4$ moles of $HIO_4$ yields $4$ moles of formic acid $(HCOOH)$ and $1$ mole of formaldehyde $(

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(C) In reaction $(i)$,the oxidation of aldopentose with $4$ moles of $HIO_4$ yields $4$ moles of formic acid $(HCOOH)$ and $1$ mole of formaldehyde $(HCHO)$. $CHO-(CHOH)_3-CH_2OH \xrightarrow{4HIO_4} 4HCOOH + HCHO$ In reaction $(ii)$,the oxidation of hexitol with $5$ moles of $HIO_4$ yields $4$ moles of formic acid $(HCOOH)$ and $2$ moles of formaldehyde $(HCHO)$. $CH_2OH-(CHOH)_4-CH_2OH \xrightarrow{5HIO_4} 4HCOOH + 2HCHO$ Ratio of moles of formic acid = $4 / 4 = 1$.

$(i) \ CHO-(CHOH)_3-CH_2OH \xrightarrow{4HIO_4} \text{Product}$
$(ii) \ CH_2OH-(CHOH)_4-CH_2OH \xrightarrow{5HIO_4} \text{Product}$
\text{The ratio of moles of formic acid obtained in reaction } $(i)$ \text{ and reaction } (ii) \text{ is:}

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$(i) \ CHO-(CHOH)_3-CH_2OH \xrightarrow{4HIO_4} \text{Product}$ $(ii) \ CH_2OH-(CHOH)_4-CH_2OH \xrightarrow{5HIO_4} \text{Product}$ \text{The ratio of moles of formic acid obtained in reaction } $(i)$ \text{ and reaction } (ii) \text{ is:}