The reaction CH_3-C(=O)-CH_2-C(CH_3)_2-CHO xr | vedclass

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(B) The given reactant is $CH_3-C(=O)-CH_2-C(CH_3)_2-CHO$. In the presence of $KOH$ and $H_2O$,an intramolecular aldol condensation occurs. The enolat

Vedclass · Accepted Answer

$4,4-$dimethylcyclopent$-2-$en$-1-$one

Vedclass · Answer

(B) The given reactant is $CH_3-C(=O)-CH_2-C(CH_3)_2-CHO$. In the presence of $KOH$ and $H_2O$,an intramolecular aldol condensation occurs. The enolate is formed at the $CH_2$ group adjacent to the ketone,which then attacks the aldehyde carbonyl carbon. This forms a five-membered ring. Subsequent dehydration leads to the formation of the $\alpha,\beta$-unsaturated ketone,which is $4,4-	ext{dimethylcyclopent-2-en-1-one}$.

The reaction $CH_3-C(=O)-CH_2-C(CH_3)_2-CHO \xrightarrow{KOH, H_2O} (A)$; Product $A$ is

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