Observe the following set of reactions. What | vedclass

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(C) $1$. The conversion of benzoyl chloride $(C_6H_5COCl)$ to benzaldehyde $(C_6H_5CHO)$ is the Rosenmund reduction,which uses $H_2 | Pd-BaSO_4$ as th

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$H_2 | Pd-BaSO_4 ; (CH_3)_2Cd ; C_6H_5CH=CH-C(=O)C_6H_5$

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(C) $1$. The conversion of benzoyl chloride $(C_6H_5COCl)$ to benzaldehyde $(C_6H_5CHO)$ is the Rosenmund reduction,which uses $H_2 | Pd-BaSO_4$ as the reagent. Thus,$X = H_2 | Pd-BaSO_4$.$2$. The conversion of benzoyl chloride $(C_6H_5COCl)$ to acetophenone $(C_6H_5COCH_3)$ is achieved using a dialkyl cadmium reagent,$(CH_3)_2Cd$. Thus,$Y = (CH_3)_2Cd$.$3$. The reaction between benzaldehyde $(C_6H_5CHO)$ and acetophenone $(C_6H_5COCH_3)$ in the presence of $OH^-$ at $293 \ K$ is a Claisen-Schmidt condensation reaction. The major product $Z$ is benzalacetophenone (chalcone),which has the structure $C_6H_5CH=CH-C(=O)C_6H_5$.

Column-$I$ (Reactants)	Column-$II$ (Products)
$(A)$ $HCHO + \text{Cyclohexyl-MgBr} \rightarrow X \xrightarrow{H_2O} Y$	$(i)$ $\text{Benzenesulfonic acid}$
$(B)$ $\text{2-oxocyclohexylacetate} \xrightarrow{NaBH_4}$	$(ii)$ $\text{Cyclohexylmethanol}$
$(C)$ $HCHO + CH_3-CH_2-CH(CH_3)-CH_2-MgBr \rightarrow X \xrightarrow{H_2O} Y$	$(iii)$ $\text{2-(2-hydroxycyclohexyl)acetate}$
$(D)$ $\text{Benzene} + \text{Oleum}$	$(iv)$ $Y = \text{3-methylpentan-1-ol}$

Observe the following set of reactions. What are $X, Y$ and $Z$ respectively?

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Consider the following sequence of reactions.
$C_6H_5COONa$ $\xrightarrow[\Delta]{NaOH/CaO} X$ $\xrightarrow[\text{Anhy. } AlCl_3]{CO/HCl} Y$ $\xrightarrow[NaOH]{\text{conc. }} A + B$.
If $A$ is the reduction product of $Y$,what is $B$?

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