$K_b$ for $NH_4OH$ is $1.8 \times 10^{-5}$. The $[OH^{-}]$ of $0.1 \ M \ NH_4OH$ is

  • A
    $5.0 \times 10^{-2}$
  • B
    $4.20 \times 10^{-3}$
  • C
    $1.34 \times 10^{-3}$
  • D
    $1.8 \times 10^{-6}$

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If two acids of equimolar concentration are taken,then which option is correct?

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