$Ph-O-CH_2-Ph \xrightarrow{HI} A + B$ will be

  • A
    $Ph-OH + Ph-CH_2-I$
  • B
    $Ph-I + Ph-CH_2-I$
  • C
    $Ph-I + Ph-CH_2-OH$
  • D
    $Ph-OH + Ph-CH_2-OH$

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Action of hydrogen iodide on anisole gives,

Which of the following will not give ether as a product?

An ether $(A)$,$C_5H_{12}O$,when heated with excess of hot concentrated $HI$ produced two alkyl halides which when treated with $NaOH$ yielded compounds $(B)$ and $(C)$. Oxidation of $(B)$ and $(C)$ gave a propanone and an ethanoic acid respectively. The $IUPAC$ name of the ether $(A)$ is

Match the starting materials given in Column-$I$ with the products formed by these (Column-$II$) in the reaction with $HI$.
Column-$I$Column-$II$
$(A)$ $CH_3-O-CH_3$$(1)$ $C_6H_5OH + CH_3I$
$(B)$ $(CH_3)_2CH-O-CH_3$$(2)$ $(CH_3)_3C-I + CH_3OH$
$(C)$ $(CH_3)_3C-O-CH_3$$(3)$ $C_6H_5I + CH_3OH$
$(D)$ $C_6H_5-O-CH_3$$(4)$ $CH_3OH + CH_3I$
$(5)$ $(CH_3)_2CHOH + CH_3I$
$(6)$ $(CH_3)_2CH-I + CH_3OH$
$(7)$ $(CH_3)_3COH + CH_3I$

Which products are obtained when methoxy ethane is heated with $HI$?

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