Identify Y in the following reaction sequence | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2 + HCl$ at $0-5^{\circ}C$ to form benzene diazonium chloride $(

Vedclass · Accepted Answer

Benzene

Vedclass · Answer

(B) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2 + HCl$ at $0-5^{\circ}C$ to form benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$,which is $X$.$2$. Benzene diazonium chloride $(X)$ reacts with hypophosphorous acid $(H_3PO_2)$ and water to undergo reduction,yielding benzene $(C_6H_6)$ as the final product $Y$.Therefore,$Y$ is benzene.

Identify $Y$ in the following reaction sequence:
$C_6H_5NH_2$ $\xrightarrow[5^{\circ}C]{NaNO_2 + HCl} X$ $\xrightarrow{H_3PO_2 / H_2O} Y$

Similar Questions

The foul-smelling compound formed during the carbylamine reaction is:

Identify the reagent $R$ in the following reaction:
$C_6H_5NO_2 \xrightarrow{R} C_6H_5NHOH$

The correct order of basicity in amines is:
$(i)$ $C_6H_5NH_2$
$(ii)$ $CH_3NH_2$
$(iii)$ $(CH_3)_2NH$
$(iv)$ $(CH_3)_3N$

$H_3CCONH_2 + Br_2 + 4NaOH \longrightarrow Y + Na_2CO_3 + 2NaBr + 2H_2O$
What is $Y$ in the above reaction?

Which of the following is the most basic substance?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify $Y$ in the following reaction sequence:$C_6H_5NH_2$ $\xrightarrow[5^{\circ}C]{NaNO_2 + HCl} X$ $\xrightarrow{H_3PO_2 / H_2O} Y$