H_3CCONH_2 + Br_2 + 4NaOH longrightarrow Y + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given reaction is the Hofmann bromamide degradation reaction.In this reaction,a primary amide $(RCONH_2)$ reacts with bromine $(Br_2)$ and a s

Vedclass · Accepted Answer

$H_3CNH_2$

Vedclass · Answer

(B) The given reaction is the Hofmann bromamide degradation reaction.In this reaction,a primary amide $(RCONH_2)$ reacts with bromine $(Br_2)$ and a strong base ($NaOH$ or $KOH$) to form a primary amine $(RNH_2)$ with one carbon atom less than the original amide.The balanced chemical equation is:$H_3CCONH_2 + Br_2 + 4NaOH \longrightarrow CH_3NH_2 + Na_2CO_3 + 2NaBr + 2H_2O$Comparing this with the given reaction,$Y$ is $CH_3NH_2$ (methylamine),which corresponds to option $B$.

$H_3CCONH_2 + Br_2 + 4NaOH \longrightarrow Y + Na_2CO_3 + 2NaBr + 2H_2O$
What is $Y$ in the above reaction?

Similar Questions

Which of the following statements is incorrect for primary amines?

Nitration of aniline in a strong acidic medium gives a significant amount of $m$-nitroaniline because:

The correct sequential order of the reagents for the given reaction is:

The major product of the reaction is

Which of the options correctly represents the basicity order for these compounds?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$H_3CCONH_2 + Br_2 + 4NaOH \longrightarrow Y + Na_2CO_3 + 2NaBr + 2H_2O$What is $Y$ in the above reaction?