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(C) $HCl$ does not show the peroxide effect (Kharasch effect). The reaction proceeds via Electrophilic Addition Reaction $(EAR)$.$1$. Protonation of t

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$1-$chloro$-1-$methylcyclohexane

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(C) $HCl$ does not show the peroxide effect (Kharasch effect). The reaction proceeds via Electrophilic Addition Reaction $(EAR)$.$1$. Protonation of the alkene leads to the formation of a more stable carbocation.$2$. The $1$-methylcyclopentyl carbocation undergoes ring expansion to form a more stable $6$-membered ring (cyclohexyl carbocation).$3$. The chloride ion $(Cl^-)$ then attacks the carbocation to form $1$-chloro-$1$-methylcyclohexane as the major product.

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Similar Questions

Reactivity order of alkenes towards electrophilic addition reaction:
$I: CH_2=CH_2$
$II: CH_3-CH=CH_2$
$III: CH_3-C(CH_3)=CH_2$
$IV: CH_2=CH-Cl$

The percentage composition of an organic compound $A$ is: carbon = $85.71 \%$ and hydrogen = $14.29 \%$. Its vapour density is $14$. Consider the following reaction sequence:
$A$ $\xrightarrow{Cl_2/H_2O} B$ $\xrightarrow[(ii) H_3O^+]{(i) KCN/EtOH} C$
Identify $C$.

How many products are formed in the following reaction?
$1,4$-dimethylcyclohex-$1$-ene + $HBr \rightarrow$ ?

Identify $A$ and $B$ in the following reaction:
Propene $\xrightarrow{\text{HBr (Benzoyl peroxide)}}$ $A$ (Major product)
Propene $\xrightarrow{\text{HI}}$ $B$ (Major product)

Which reaction will yield $CH_2 = C = CH_2$?

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