Identify A and B in the following reaction:Pr | vedclass

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(A) $1$. The reaction of propene with $HBr$ in the presence of benzoyl peroxide follows the anti-Markovnikov addition (peroxide effect or Kharasch eff

Vedclass · Accepted Answer

$A: CH_3-CH_2-CH_2-Br$$B: CH_3-CH(I)-CH_3$

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(A) $1$. The reaction of propene with $HBr$ in the presence of benzoyl peroxide follows the anti-Markovnikov addition (peroxide effect or Kharasch effect). In this reaction,the $Br^-$ adds to the less substituted carbon atom of the double bond,resulting in $1$-bromopropane $(CH_3-CH_2-CH_2-Br)$ as the major product $(A)$.$2$. The reaction of propene with $HI$ follows the Markovnikov addition rule. In this reaction,the $H^+$ adds to the carbon with more hydrogen atoms,and the $I^-$ adds to the more substituted carbon atom,resulting in $2$-iodopropane $(CH_3-CH(I)-CH_3)$ as the major product $(B)$.

Identify $A$ and $B$ in the following reaction:
Propene $\xrightarrow{\text{HBr (Benzoyl peroxide)}}$ $A$ (Major product)
Propene $\xrightarrow{\text{HI}}$ $B$ (Major product)

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Identify $A$ and $B$ in the following reaction:Propene $\xrightarrow{\text{HBr (Benzoyl peroxide)}}$ $A$ (Major product)Propene $\xrightarrow{\text{HI}}$ $B$ (Major product)