20 mL of CO_2 gas are passed over excess of | vedclass

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(D) The balanced chemical equation is:$CO_{2(g)} + C_{(s)} 	o 2CO_{(g)}$According to the stoichiometry of the reaction,$1$ mole of $CO_2$ produces $2

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$40$

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(D) The balanced chemical equation is:$CO_{2(g)} + C_{(s)} 	o 2CO_{(g)}$According to the stoichiometry of the reaction,$1$ mole of $CO_2$ produces $2$ moles of $CO$ gas.Since the volume of a gas is directly proportional to the number of moles at constant temperature and pressure (Avogadro's Law),the volume ratio is the same as the mole ratio.Therefore,$1 \ mL$ of $CO_2$ produces $2 \ mL$ of $CO$.For $20 \ mL$ of $CO_2$,the volume of $CO$ produced is:$20 \ mL 	imes 2 = 40 \ mL$.

$20 \ mL$ of $CO_2$ gas are passed over excess of red hot coke. The volume of $CO$ evolved is ............. $mL$.
$CO_{2(g)} + C_{(s)} \to 2CO_{(g)}$

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$20 \ mL$ of $CO_2$ gas are passed over excess of red hot coke. The volume of $CO$ evolved is ............. $mL$.$CO_{2(g)} + C_{(s)} \to 2CO_{(g)}$