The IUPAC name of the given compound is: | vedclass

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(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority and is attached to the ring,so the pare

Vedclass · Accepted Answer

$4-$Formyl$-2-$oxocyclohexanecarboxylic acid

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(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority and is attached to the ring,so the parent name is cyclohexanecarboxylic acid. $2$. Number the ring: Start numbering from the carbon attached to the $-COOH$ group as $C-1$. $3$. Assign positions to other substituents: The ketone group $(=O)$ is at position $2$ and the formyl group $(-CHO)$ is at position $4$. $4$. Combine the names: The substituents are $4-$formyl and $2-$oxo. Arranging them alphabetically,we get $4-$formyl$-2-$oxocyclohexanecarboxylic acid.

The $IUPAC$ name of the given compound is:

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