$CH_3-C \equiv CH$ $\xrightarrow{Na} X$ $\xrightarrow{CH_3-Cl} Y$,$Y$ is

Given below are two statements:
Statement $I$: One mole of propyne reacts with excess of sodium to liberate half a mole of $H_2$ gas.
Statement $II$: Four $g$ of propyne reacts with $NaNH_2$ to liberate $NH_3$ gas which occupies $224 \ mL$ at $STP$.
In the light of the above statements,choose the most appropriate answer from the options given below:

$A$ $\xrightarrow[1\% \ HgSO_4]{20\% \ H_2SO_4} B$ $\xrightarrow{I_2 + NaOH} C + C_6H_5COONa$. The reactant $A$ is

What is the product when acetylene reacts with hypochlorous acid $(HOCl)$?

The correct order of acidity of the following compounds is

$I. CH_3-C \equiv CH$

$II. F_3C-C \equiv CH$

$III. CH_3-C \equiv C-CH_3$

$IV. CH_3-CH=CH-CH_3$

Predict the correct intermediate and product in the following reaction: $CH_3-C \equiv CH \xrightarrow[HgSO_4]{H_2O, H_2SO_4} \text{Intermediate } (A) \to \text{Product } (B)$