S-O bond length is maximum in | vedclass

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(D) The $S-O$ bond length depends on the extent of $p\pi-d\pi$ back-bonding from the oxygen atom to the sulfur atom. Greater back-bonding leads to mor

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$SO(CH_3)_2$

Vedclass · Answer

(D) The $S-O$ bond length depends on the extent of $p\pi-d\pi$ back-bonding from the oxygen atom to the sulfur atom. Greater back-bonding leads to more double bond character,which decreases the bond length. In $SOF_2$,the highly electronegative fluorine atoms withdraw electron density from sulfur,increasing the effective nuclear charge on sulfur,which enhances the $p\pi-d\pi$ back-bonding from oxygen to sulfur,resulting in a shorter $S-O$ bond. In $SO(CH_3)_2$,the methyl groups are electron-donating,which decreases the $p\pi-d\pi$ back-bonding,thereby increasing the $S-O$ bond length. Therefore,the $S-O$ bond length is maximum in $SO(CH_3)_2$.

$S-O$ bond length is maximum in

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