$BCl_3$ is a planar molecule while $NCl_3$ is pyramidal. This is because......
- A$BCl_3$ has no lone pair of electrons,whereas $NCl_3$ has one lone pair of electrons.
- B$B-Cl$ bond is more reactive than $N-Cl$ bond.
- CNitrogen atom is smaller than boron atom.
- D$N-Cl$ bond is more covalent than $B-Cl$ bond.
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Similar Questions
The compound that has the largest $H-M-H$ bond angle $(M = N, O, S, C)$ is :
DifficultJEE MAIN 2020
View SolutionThe number of species below that have two lone pairs of electrons on their central atom is ..... . (Round off to the nearest integer)
$SF_{4}, BF_{4}^{-}, ClF_{3}, AsF_{3}, PCl_{5}, BrF_{5}, XeF_{4}, SF_{6}$
$SF_{4}, BF_{4}^{-}, ClF_{3}, AsF_{3}, PCl_{5}, BrF_{5}, XeF_{4}, SF_{6}$
Which of the following molecules is linear?
Medium
View SolutionThe number of lone pairs of electrons present on $Xe$ in $XeF_4$ is
Match the following:
List-$I$ (Molecule) List-$II$ (Shape) $A$. $XeF_4$ $I$. Square pyramidal $B$. $ClF_3$ $II$. Pentagonal bipyramidal $C$. $BrF_5$ $III$. Square planar $D$. $IF_7$ $IV$. Bent $T$-shape
| List-$I$ (Molecule) | List-$II$ (Shape) |
|---|---|
| $A$. $XeF_4$ | $I$. Square pyramidal |
| $B$. $ClF_3$ | $II$. Pentagonal bipyramidal |
| $C$. $BrF_5$ | $III$. Square planar |
| $D$. $IF_7$ | $IV$. Bent $T$-shape |
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