The electron affinity of sulfur is........

  • A
    Greater than $O$ and $Se$.
  • B
    Greater than $O$ but less than $Se$.
  • C
    Less than $O$ but greater than $Se$.
  • D
    Equal to $O$ and $Se$.

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Similar Questions

The formation of the oxide ion $O_{(g)}^{2-}$ requires first an exothermic and then an endothermic step as shown below. This is because
$O_{(g)} + e^{-} \rightarrow O_{(g)}^{-}; \Delta H^{o} = -142 \ kJ \ mol^{-1}$
$O_{(g)}^{-} + e^{-} \rightarrow O_{(g)}^{2-}; \Delta H^{o} = 844 \ kJ \ mol^{-1}$

Electron affinity depends on

Electron gain enthalpy values $(\Delta_{eg} H)$ (in $kJ \ mol^{-1}$) of elements $X$,$Y$ and $Z$ are $-349$,$-200$ and $-295$ respectively. $X$,$Y$ and $Z$ are respectively

The process requiring the absorption of energy is

The formation of the oxide ion,$O^{2-}_{(g)}$ from an oxygen atom requires first an exothermic and then an endothermic step as shown below:
$O_{(g)} + e^- \to O^{-}_{(g)} ; \Delta_f H^o = -141 \ kJ \ mol^{-1}$
$O^{-}_{(g)} + e^- \to O^{2-}_{(g)} ; \Delta_f H^o = +780 \ kJ \ mol^{-1}$
Thus,the process of formation of $O^{2-}$ in the gas phase is unfavourable even though $O^{2-}$ is isoelectronic with neon. This is due to the fact that,

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