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(A) The reaction of an alkyne with excess $HOCl$ proceeds through electrophilic addition.$1$. $HOCl$ adds across the triple bond to form a chlorohydri

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(A) The reaction of an alkyne with excess $HOCl$ proceeds through electrophilic addition.$1$. $HOCl$ adds across the triple bond to form a chlorohydrin intermediate.$2$. Since $HOCl$ is in excess, the addition occurs twice at the same carbon atom (following Markovnikov's rule, where the $OH$ group attaches to the more substituted carbon).$3$. This results in a geminal diol intermediate, which is unstable and undergoes dehydration to form a ketone.$4$. The final product is $Cyclohexyl-C(=O)-CHCl_2$.

What is the major product of the following reaction?
$Cyclohexyl-C \equiv CH \xrightarrow{HOCl \text{ (excess)}} \text{major product}$

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What is the major product of the following reaction?$Cyclohexyl-C \equiv CH \xrightarrow{HOCl \text{ (excess)}} \text{major product}$