What is the product A in the given reaction?C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of an alkyne with $H^+ / Hg^{2+}$ is an acid-catalyzed hydration reaction,which follows Markovnikov's rule.For the alkyne $C_6H_5-C \

Vedclass · Accepted Answer

$C_6H_5-CO-CH_2-CH_3$

Vedclass · Answer

(C) The reaction of an alkyne with $H^+ / Hg^{2+}$ is an acid-catalyzed hydration reaction,which follows Markovnikov's rule.For the alkyne $C_6H_5-C \equiv C-CH_3$,the addition of water occurs across the triple bond.The $OH^-$ group attaches to the carbon atom that is more substituted or stabilized by the phenyl group,leading to the formation of an enol intermediate.Specifically,the intermediate is $C_6H_5-C(OH)=CH-CH_3$.This enol then undergoes tautomerization to form the more stable ketone,which is $C_6H_5-CO-CH_2-CH_3$ (propiophenone derivative).However,looking at the options provided,option $C$ represents the final ketone product.

What is the product $A$ in the given reaction?
$C_6H_5-C \equiv C-CH_3 \xrightarrow{H^+ / Hg^{2+}} A$

Similar Questions

What is the major product of the following reaction? $CH_3-C \equiv C-CH_2-CH_3 \xrightarrow{1 \ mol \ of \ Cl_2} \text{?}$

Acetylene molecules contain

Ethene can be separated from acetylene by passing the mixture through :

The reagents to carry out the following conversion are:

$2-$Hexyne gives $trans-2-$hexene on treatment with:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is the product $A$ in the given reaction?$C_6H_5-C \equiv C-CH_3 \xrightarrow{H^+ / Hg^{2+}} A$