$CH_3CHO \xrightarrow{LiAlH_4} CH_3CH_2OH$
Which nucleophile is added in this reaction?

Benzene carbaldehyde (benzaldehyde) is reacted with concentrated $NaOH$ solution to give the products $A$ and $B$. The product $A$ can be used as a food preservative and the product $B$ is an aromatic hydroxy compound where the $OH$ group is linked to an $sp^3$ hybridized carbon atom next to the benzene ring. The products $A$ and $B$ are respectively,

In the given reaction,what will be $A$ and $B$ respectively?
$(CH_3)_2CO$ $\xrightarrow{NaCN/HCl} A$ $\xrightarrow{H_3O^+} B$

$Ph-CO-CH_3 \xrightarrow[H_2O]{Mg-Hg}$ Product. The main product is:

Which of the following compounds undergoes the Cannizzaro reaction?

The option$(s)$ with the correct sequence of reagents for the conversion of $P$ to $Q$ is(are):
$(A)$ $i$) Lindlar's catalyst,$H_2$; $ii$) $SnCl_2 / HCl$; $iii$) $NaBH_4$; $iv$) $H_3O^{+}$
$(B)$ $i$) Lindlar's catalyst,$H_2$; $ii$) $H_3O^{+}$; $iii$) $SnCl_2 / HCl$; $iv$) $NaBH_4$
$(C)$ $i$) $NaBH_4$; $ii$) $SnCl_2 / HCl$; $iii$) $H_3O^{+}$; $iv$) Lindlar's catalyst,$H_2$
$(D)$ $i$) Lindlar's catalyst,$H_2$; $ii$) $NaBH_4$; $iii$) $SnCl_2 / HCl$; $iv$) $H_3O^{+}$