PhMgBr [Excess] + CH_3COCl xrightarrow{H_3O^+ | vedclass

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(B) $1.$ When an excess of Grignard reagent $(PhMgBr)$ reacts with an acid chloride $(CH_3COCl)$,the reaction occurs in two steps.$2.$ Nucleophilic ac

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$Ph-C(OH)(Ph)-CH_3$

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(B) $1.$ When an excess of Grignard reagent $(PhMgBr)$ reacts with an acid chloride $(CH_3COCl)$,the reaction occurs in two steps.$2.$ Nucleophilic acyl substitution: The first equivalent of $PhMgBr$ reacts with $CH_3COCl$ to form acetophenone $(Ph-C(=O)-CH_3)$ and $MgBrCl$.$3.$ Nucleophilic addition: Since the Grignard reagent is in excess,a second equivalent of $PhMgBr$ attacks the carbonyl group of acetophenone to form an alkoxide intermediate,which upon acid workup $(H^+)$ yields $1,1$-diphenylethanol $(Ph-C(OH)(Ph)-CH_3)$.Reaction:$CH_3COCl + PhMgBr$ $\rightarrow Ph-C(=O)-CH_3$ $\xrightarrow{PhMgBr} Ph-C(OMgBr)(Ph)-CH_3$ $\xrightarrow{H^+} Ph-C(OH)(Ph)-CH_3$.

$PhMgBr$ [Excess] + $CH_3COCl \xrightarrow{H_3O^+}$
The final product of the above reaction is:

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$PhMgBr$ [Excess] + $CH_3COCl \xrightarrow{H_3O^+}$ The final product of the above reaction is: