Ph-CH=CH-Ph xrightarrow[CCl_4]{Cl_2} X xright | vedclass

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(B) The reaction sequence is as follows:$1.$ Chlorination of stilbene: $Ph-CH=CH-Ph + Cl_2 \xrightarrow{CCl_4} Ph-CHCl-CHCl-Ph$ $(X)$$2.$ Double dehyd

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(B) The reaction sequence is as follows:$1.$ Chlorination of stilbene: $Ph-CH=CH-Ph + Cl_2 \xrightarrow{CCl_4} Ph-CHCl-CHCl-Ph$ $(X)$$2.$ Double dehydrohalogenation: $Ph-CHCl-CHCl-Ph + 2NaNH_2 ightarrow Ph-C \equiv C-Ph$ $(Y)$$3.$ Partial hydrogenation: $Ph-C \equiv C-Ph + H_2 \xrightarrow{Pd/BaSO_4} 	ext{cis}-Ph-CH=CH-Ph$ $(Z)$.Lindlar's catalyst $(Pd/BaSO_4)$ performs syn-addition of hydrogen to alkynes,yielding cis-alkenes. The structure of cis-stilbene corresponds to option $B$.

$Ph-CH=CH-Ph$ $\xrightarrow[CCl_4]{Cl_2} X$ $\xrightarrow{2NaNH_2} Y$ $\xrightarrow[BaSO_4]{H_2+Pd} Z$. Product $Z$ is

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