M text{ (Salt)} + text{Dil. } HCl xrightarrow | vedclass

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(C) $1$. $BaS_2O_3 + HCl \xrightarrow{	ext{warm}} BaCl_2 + SO_2 \uparrow + S \downarrow$. $SO_2$ does not oxidize $Fe^{2+}$ to $Fe^{3+}$,so the solut

Vedclass · Accepted Answer

$AgNO_2$

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(C) $1$. $BaS_2O_3 + HCl \xrightarrow{	ext{warm}} BaCl_2 + SO_2 \uparrow + S \downarrow$. $SO_2$ does not oxidize $Fe^{2+}$ to $Fe^{3+}$,so the solution remains green.$2$. $Ag_2SO_3 + HCl \xrightarrow{	ext{warm}} AgCl \downarrow + SO_2 \uparrow$. $SO_2$ does not oxidize $Fe^{2+}$,so the solution remains green.$3$. $AgNO_2 + HCl \xrightarrow{	ext{warm}} AgCl \downarrow + NO_2 \uparrow$. $NO_2$ is an oxidizing agent that oxidizes $Fe^{2+}$ to $Fe^{3+}$,turning the $FeSO_4$ solution yellow.$4$. $Pb(NO_3)_2$ does not react with dilute $HCl$ to produce a gas.Therefore,the correct salt is $AgNO_2$.

$M \text{ (Salt)} + \text{Dil. } HCl \xrightarrow{\text{Warm}} N \uparrow + P \downarrow$. Gas $N$ changes the colour of $FeSO_4$ solution into a yellow solution. Then,salt $M$ in the above reaction is:

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