The ratio of densities of two gases is 1 : 2. | vedclass

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(A) From the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$.Substituting $n$,we get $PV = \frac{m}{M}RT$.Rearranging for density $(d = \frac{m}

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$1 : 1$

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(A) From the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$.Substituting $n$,we get $PV = \frac{m}{M}RT$.Rearranging for density $(d = \frac{m}{V})$,we get $P = \frac{dRT}{M}$.Since the molar masses $(M)$ are equal,the relationship is $P \propto d 	imes T$.Given the ratio of densities $\frac{d_1}{d_2} = \frac{1}{2}$ and the ratio of temperatures $\frac{T_1}{T_2} = \frac{2}{1}$.The ratio of pressures is $\frac{P_1}{P_2} = \frac{d_1}{d_2} 	imes \frac{T_1}{T_2} = \frac{1}{2} 	imes \frac{2}{1} = \frac{1}{1}$.Therefore,the ratio of their pressures is $1 : 1$.

The ratio of densities of two gases is $1 : 2$. If the ratio of their temperatures is $2 : 1$,find the ratio of their corresponding pressures. (Assume the molar masses of the gases are equal.)

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